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Post by BeetrootBertie on Sept 2, 2021 18:47:56 GMT
My mate is having a go at writing a choose your own adventure type book and we've got a bit stumped trying figure out some dice-rolling probabilities.
If the player has 3 dice (D20, D12 and D10) and rolls all simultaneously, what is (or how can I work out) the odds of any one of those having a value of 3 or less?
FWIW I'm crap at maths.
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Post by 😎 on Sept 2, 2021 18:51:43 GMT
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Post by 😎 on Sept 2, 2021 18:53:07 GMT
Oh wait, that only handles one die type. Try this, more fiddly - anydice.com/ |
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Post by RadicalRex on Sept 2, 2021 18:57:54 GMT
17/20 * 9/12 * 7/10 = 0.85 * 0.75 * 0.7 = 0.446
The chance of not rolling a 3 or less is is 44.6%, therefore the chance of having a 3 or less with any of them on a roll is 55.4%.
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Post by BeetrootBertie on Sept 2, 2021 19:13:43 GMT
Awesome. Thanks so much - Font Geek to the rescue!
Omni calculator was helpful, I think - I could get the probability of rolling at least one 1-3 using 3 of same sided dice at least, so I'd just plumped somewhere between the results for x3 D10 and those for x3 D20 to get a rough ballpark of 52.5% and guessed it would be a bit higher due to the D12 but didn't have a clue how to get the exact amount.
Thanks for showing the working out too.
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Post by RadicalRex on Sept 2, 2021 19:37:17 GMT
Not trying to be an arse, and tbh I know very little about not sounding like an arse, but the exact value is 55.375%.
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